Question

Vă rogg,ajutați-măă,urgent! 
|x+1|=2
|-x-3|=1
$\sqrt{2} . ( \sqrt{3}- \sqrt{2})- \sqrt{6} +3$

Answer 1

/ x+1/=2 => x = 1 /1+1/=/2/=2
/-x-3/=1 => x = /-1/=1
 =
RD -radical
RD6 -2 -RD6+3 = 1 ( RD6 se reduce -RD6 )