Question

Va rogg foarte mult sa ma ajutați cu problema din imagine!! măcar primul sub punct...​

Answer 1

$\displaystyle\it\\19.1~ecuatiile~trebuiesc~rezolvate~in~\mathbb{R}\times\mathbb{R},~nu~in~\mathbb{Z}\times\mathbb{Z}.\\-------------------------\\a) x-2y+8=0 \implies x-2y=8 \implies x=8-2y=2(4-y).\\\\b)\frac{1}{3}x-\frac{1}{4}y-2=0 |\cdot 12 \implies 4x-3y-24=0 \implies\\4x-3y=24 \implies 4x=24+3y \implies x=\frac{3}{4} y+6.\\\\c)x+y\sqrt{2}-\sqrt{3}=0 \implies x=\sqrt{3}-y\sqrt{2}.\\\\d)4(x-y)+3y=-x+3 \implies 4x-4y+3y=3-x \implies\\4x-y=3-x \implies 4x-3+x=y \implies y=5x-3.$

$\displaystyle\it\\e) 4x-5y=0 \implies 4x=5y \implies x=\frac{5}{4}y.\\---------------------\\19.2.\\pentru~a)\\\bigcap Ox: y=0 \implies x=-8,avem~punctul~de~coordonate~A(-8,0).\\\bigcap Oy: x=0 \implies y=4,avem~punctul~de~coordonate~B(0,4).\\reprezentam~punctele~A~si~B~si~duci~dreapta~prin~aceste~puncte.\\pentru~b)\\\bigcap Ox : y=0 \implies x=6,avem~punctul~de~coordonate~A(6,0).\\\bigcap Oy : x=0 \implies x=-8,avem~punctul~de~coordonate~B(0,-8).$