Question

va rogg mult , imi trebuie urgent in seara asta​

Answer 1

Răspuns:

AB=18cm

CD=0,14m=14cm

P=AB+2BC+CD

P=18+14+2BC

P=32+2BC

A=[(AB+CD)×h]/2

A=[(18+14)×h]/2

A=(32×h)/2

A=16×h

ABCD trapez isoscel

BD⊥AD

⇒ formeazâ un pătrat

⇒ CD=h=14cm

A=16×h

A=16×14

A=224cm²

Fie DM⊥AB

△DMA dreptunghic

h=DM=14cm

AM=AB-DA-AM

2AM=18-14=4

AM=2cm

△DMA dreptunghic

m∢M=90⁰

teorema lui Pitagora

AD²=AM²+DM²

AD²=2²+14²

AD²=4+196

AD²=200

AD=√200

AD=10√2

P=32+2×10√2

P=32+20√2

P=4(8+5√2)cm