Question

Va rogg, repedee!!Sper sa intelegeti!

Answer 1

a) ΔADB: DM⊥AB → DMB = 90° → DM² = DB² - MB²; DM² = 100-58 = 75 → DM = 5√3cm. DM² = AM x MB → 75 = 5 x AM → am = 15 cm → AB = AM + MB = 20 cm. ΔABD (ABD = 90°) → AD² = AB² - DB² → AD² = 400 - 100 = 300 cm → AD = 10√3 cm. PΔADB: AD + DB + AB = 10√3 + 10 + 20 = 10 (√3 + 3) cm.

b) SΔABC = (AD x BC)/2 = (10√3 x 20)/2 = 100√3 cm²