Question

va roggg dau coroanăă​

Answer 1

Explicație pas cu pas:

$n = \frac{4}{3} - \frac{4}{3} \cdot \Big[ \frac{4}{3} - {(0.(3))}^{2}\Big] : 4 \frac{8}{9} = \\ = \frac{4}{3} - \frac{4}{3} \cdot \Big[ \frac{4}{3} - {\Big( \frac{3^{(3} }{9} \Big)}^{2}\Big] : \frac{44}{9}\\ = \frac{4}{3} - \frac{4}{3} \cdot \Big[ \frac{4}{3} - {\Big( \frac{1}{3} \Big)}^{2}\Big] : \frac{44}{9}\\ = \frac{4}{3} - \frac{4}{3} \cdot \Big( \frac{^{3)} 4}{3} - \frac{1}{9}\Big) \cdot \frac{9}{44}\\ = \frac{4}{3} - \frac{4}{3} \cdot \frac{12 - 1}{9} \cdot \frac{9}{44} \\ = \frac{4}{3} - \frac{ \not4}{3} \cdot \frac{\not11}{ \not9} \cdot \frac{ \not9}{\not44}\\ = \frac{4}{3} - \frac{1}{3} = \frac{4 - 1}{3} = \frac{3}{3} = \bf 1$

q.e.d.