Question

Va roggg!!! Este unrgentttt!!!!​

Answer 1

Răspuns:

1)

folosind teorema lui Pitagora

4² = x² + x²

16 = 2x² => x² = 8 => x = √8 => x = 2√2

2)

folosind Pitagora:

3² = y² + 2,5²

9 = y² + 6,25

y² = 9 - 6,25

y² = 2,75

y = √2,75

3)

folosind pitagora

4² = 2² + z²

16 = 4 + z²

z² = 16 - 4

z² = 12

z = √12

z = 2√3

4)

folosind Pitagora

4² = 3² + t²

16 = 9 + t²

t² = 16 - 9

t² = 7

t = √7

5)

$\tan(30) = \frac{u}{3}$

$\frac{1}{ \sqrt{3} } = \frac{u}{3}$

$u = \frac{3}{ \sqrt{3} }$

$u = \sqrt{3}$

folosind Pitagora:

v² = 3² + u²

v² = 9 + 3

v² = 12

v = √12

v = 2√3