Question

Va roggg punctul e si h!

Answer 1

Răspuns:

Explicație pas cu pas:

e)f(x)=$tg^{2}2x$

$f'(x)=2tg(2x)^{2-1} *[tg(2x)]'=2tg(2x)*\frac{1}{cos^{2}(2x) }*(2x)'= 2tg(2x)*\frac{1}{cos^{2}(2x) }*2=4tg(2x)*\frac{1}{cos^{2}(2x) }$

h)

$f(x)=\sqrt{9x^{2} +8x-1}$

$f'(x)=\frac{1}{2*\sqrt{9x^{2} +8x-1} }* (9x^{2} +8x-1)'=\frac{1}{2*\sqrt{9x^{2} +8x-1} }*(9*2x+8)=\frac{2}{2*\sqrt{9x^{2} +8x-1} }*(9x+8)=\frac{9x+8}{2*\sqrt{9x^{2} +8x-1} }$