Question

va roggg . se considera A Bsi C trei puncte coliniare in aceasta ordine si punctele M si N mijloacele segmentelor AB si respectiv BC stiind ca :a)AB=6 cm si BC=4 cm determina lungimile segmentelor :AM NC si MN. b) AM =2cm si MN =5cm determina lungimea segmentelor AB BC si AC. c) AN=6 cm si AC=10 cm determina lungimea segmentelor NC BC si AB . +explicatie clară ​

Answer 1

a) AM=AB÷2=6cm÷2=3cm

NC=BC÷2=4cm÷2=2cm

MN=MB+BN=3cm+2cm=5cm

b)AB=AM×2=2cm×2=4cm

BN=5cm-2cm=3cm

BC=BN+NC=3cm+3cm=6cm

AC=AB+BC=4cm+6cm=10cm

c)NC=AC-AN=10cm-6cm=4cm

BC=BN congruent cu NC, deci BN=4cm

AB=AN-BN=6cm-4cm=2cm