Question

va roggg urgenttttttt​

Answer 1

Răspuns:

$\frac{3}{(2x ) {}^{2 } - 3 {}^{2} } - \frac{x + 1}{2x + 3} - \frac{x}{2x - 3}$

$\frac{3}{(2x + 3)(2x - 3)} - \frac{x + 1}{2x + 3} - \frac{x}{2x - 3}$

$\frac{3 - (x + 1)(2x - 3) - x(2x + 3)}{(2x + 3)(2x - 3)}$

$\frac{3 - 2x {}^{2} + 3x - 2x + 3 - 2x {}^{2} - 3x {}^{} }{(2x + 3)(2x - 3)}$

$\frac{(3 + 3) + ( - 2x {} ^{2} - 2x {}^{2} ) + (3x - 2x - 3x)}{(2x + 3)(2x - 3)}$

$\frac{6 - 4x {}^{2} - 2x}{(2x + 3)(2x - 3)}$

$\frac{2(3 - 2x {}^{2} - x) }{(2x + 3)(2x - 3)}$

$\frac{2( - 2x {}^{2} - x + 3)}{(2x + 3)(2x - 3)}$

$\frac{2( - (2x {}^{2} + x - 3) )}{(2x + 3)(2x - 3)}$

Atât stiu, succes! :)