Question

va roggg urgentttttttt​

Answer 1

^ - inseamna la putere

1) 25^x * 25^(-1) * V5  = 125^1 * 125^(-x)

25^x * 1/25 * V5 = 125 * 1/125^x

(5^2)^x * 1/25 * V5 = 125 * 1/125^x

(5^2)^x * V5/25 = 125 * 1/(5^3)^x

5^(2x) * V5/25 = 125 * 1/5^(3x)

5^(2x-3/2) = 125 * 1/5^(3x)

5^(2x-3/2) = 5^(-3x+3)

2x-3/2 = -3x+3

2x+3x = 3+3/2 amplificam pe 3 cu 2

5x = 9/2

x= 9/2* 1/5

x = 9/10

3) (2^2)^(x^2-2x+3) = 2^(1+3x)

2x^2-4x+6 = 1+3x

2x^2-4x-3x+6-1 = 0

2x^2-7x+5=0

2x^2-2x-5x+5 = 0

2x(x-1)-5(x-1) = 0

(x-1)(2x-5) = 0

x-1= 0 => x= 1

2x-5= 0 => x=5/2

5) (3^2)^(x+1) = (3^3)^(1-x^2)

3^(2x+2)  = 3^(3-3x^2)

2x+2 = 3-3x^2

2x+2-3+3x^2 = 0

2x-1+3x^2 = 0

3x^2+3x-x-1= 0

3x(x+1)-(x+1) = 0

(x+1)(3x-1) = 0

x+1 = 0 => x= -1

3x-1 =0=> x=1/3

La 2 si 4 nu stiu, scuze