Question

❤va rogggg❤
dau coroana ​

Answer 1

m(∡AOB)+m(∡AOC)=180°

m(∡AOB)=54°⇒m(∡AOC)=126°, dar cum aceste unghiuri sunt adiacente si m(∡AOC)>m(∡AOB)⇒∡AOB⊂∡AOC⇒m(∡AOC)=m(∡AOB)+m(∡BOC),

dar m(∡AOC)=180°-m(∡AOB)⇒180°-m(∡AOB)=m(∡AOB)+m(∡BOC)⇒

2m(∡AOB)=180°-m(∡BOC)⇒m(∡AOB)=90°-m(∡BOC)/2, dar OE bisectoarea ∡BOC⇒m(∡AOB)=90°-m(∡EOB)⇒m(∡AOE)=90°⇒OE⊥OA