Question

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Answer 1

Răspuns:

Explicație:

365g sol. HCl , c=10%

react. cu AgNO3

masa de precipitat=?

-se afla md  sol. de HCl

md= c . ms / 100

md= 10 . 365 / 100= 36,5 g HCl

36,5g                   xg

HCl + AgNO3= AgCl↓ + HNO3

36,5g                  143,5g

x= 36,5 . 143,5  / 36,5= 143, 5g AgCl

MHCl=1 +35,5=36,5-----36,5g/moli

MAgCl= 108 + 35,5= 143,5------ 143,5g/moli

Answer 2

ms=365g

C=10%

md=?

md=Cxms/100=10×365/100=36,5g

MHCl=1+35,5=36,5g/mol

MAgCl=108+ 35,5=143,5g/mol

36,5g....143,5g

AgNO3 + HCl => AgCl + HNO3

36,5g.....xg

x=36,5×143,5/36,5=143,5g AgCl.