Question

va roggggggggggggggggg

(z-3)^2+(3z-1)^2=0

Answer 1

Răspuns:

Explicație pas cu pas:

(z-3)² + (3z-1)² = 0 <=>

z² -6z +9 + 9z² -6z+1 = 0<=>

10z² -12z +10 = 0 I :2 =>

5z² - 6z +5 = 0

a = 5 ; b = -6 ; c = 5

Δ = b²-4ac = 36-4·25 = 36-100 = -64

√Δ = √-64 = 8√-1 = 8i

z₁,₂ = (-b±√Δ)/2a = (6±8i)/10

z₁ = (6-8i)/10 = (3-4i)/5

z₂ = (6+8i)/10 = (3+4i)/5