Question

VA ROGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGG DAU 20 DE PUNCTEEE
Calculati in Q:
b)36(x+6) la a2a-2(x+4)(x-1)=(2x-3)la a2a+59
f)(2x-2)la a2a-2x(2x-5)-2(2x-5)=(x+4)la a2a-(x+1)(x+6)+1
4.Determinati valorile lui a pentru care urmatoarele perechi de ecuatii sunt echivalente:
a)5x-1+2=-3+6 si x-2a+6
b)7ax-15=15-x si x supra radical3+radical150 supra radical98=0

Answer 1

b)36(x+6)²-2(x+4)(x-1)=(2x-3)²+59
36(x²+12x+36)-2(x²-x+4x-4)=4x²-12x+9+59
36x²+432x+1296-2x²-6x+8-4x²+12x-68=0
30x²+438x+1236=0
6(5x²+73x+206)=0

f)(2x-2)²-2x(2x-5)-2(2x-5)=(x+4)²-(x+1)(x+6)+1
4x²-8x+4-4x²+10x-4x+10=x²+8x+16-x²-6x-x-6+1
-2x+14=x+11
-2x-x=11-14
-3x=-3    inmultim-1
x=3/3
x=1

4.a)5x-1+2=-3+6
5x+1=3
5x=3-1
5x=2
x=2/5

x-2a+6
-2a=-x-6      inmultim -1
a=(x+6)/2
a=(2/5+6)/2=(2+30)/10=32/10=3,2

b)7ax-15=15-x
7ax+x=15+15
x(7a+1)=30
7a+1=30/x
7a=30/x-1
a=(30/x-1)/7

x/√3+√150/√98=0
√3x/3+5√6/7√2=0
√3x/3+(5√6·√2)/14=0
√3x/3+10√3/14=0
√3x/3+5√3/7=0
√3x/3=-5√3/7
7√3x=-5√3·3
x=-15√3/7√3
x=-15/7

a=(30/x-1)/7=(30/1:(-15/7)-1]/7=[-210/15-1)/7=(-210-15)/49=
=-225/49