Question

Va roog dau coroanaaaaa ex 22. ​

Answer 1

Explicație pas cu pas:

se aduc fracțiile la același numitor:

a)

$\dfrac{^{6)} x + 3}{2} + \dfrac{^{3)}x}{4} + \dfrac{^{2)}2x + 5}{6} = \dfrac{^{3)}x + 1}{4} - \dfrac{5}{12}$

$6(x + 3) + 3x + 2(2x + 5) = 3(x + 1) - 5$

$6x + 18 + 3x + 4x + 10 = 3x + 3 - 5$

$13x + 28 = 3x - 2$

$13x - 3x = - 2 - 28$

$10x = - 30 \implies x = - 3$

c)

$\dfrac{^{4)}2x + 1}{3} + \dfrac{^{2)}x}{6} - \dfrac{^{3)}3}{4} = \dfrac{35}{12} + \dfrac{^{6)} x - 4}{2}$

$4(2x + 1) + 2x - 9 = 35 + 6(x - 4)$

$8x + 4 + 2x - 9 = 35 + 6x - 24$

$10x - 5 = 6x + 11$

$4x = 16 \implies x = 4$