Question

Va roog! Este urgent!!!

9(x+1)(x-1)-(3x+1)²

Answer 1

   
[tex]\text{Folosim: }\boxed{(a+b)(a-b)=a^2 - b^2}\text{ si }\boxed{(a+b)^2=a^2+2ab +b^2} = \\ \\ 9(x+1)(x-1)-(3x+1)^2 = \\ \\ =9(x^2-1)-(9x^2+6x +1) = \\ \\ =\underline{9x^2}-9-\underline{9x^2}-6x -1 = \boxed{-6x -10 } [/tex]

Answer 2

9(x + 1)(x - 1) - (3x + 1)² = 9(x² - 1) - (9x + 6x + 1) = 9x² - 9 - 9x² - 6x - 1 = -10 - 6x