Question

Va roog mult Scoateti de sub radical
³√24=
³√250=
³√1000=
³√a³b²=
Ex2
introduceti sub radical
2√7=
-3√5=
x√xy=
a²b√ab=
0,2√5=

Answer 1

$\displaystyle\sqrt[3]{24}=\sqrt[3]{2^3*3}=2\sqrt[3]{3} \\ \sqrt[3]{250}=\sqrt[3]{2*5^3}=5\sqrt[3]{2} \\ \sqrt[3]{1000}=\sqrt[3]{10^3}=10 \\ \sqrt[3]{a^3b^2}=a\sqrt[3]{b^2} \\ \\ 2\sqrt7=\sqrt{2^2*7}=\sqrt{28} \\ -3\sqrt5=\sqrt{(-3)^2*5}=\sqrt{45} \\ x\sqrt{xy}=\sqrt{x^3y} \\ a^2b\sqrt{ab}=\sqrt{ab*(a^2b)^2}=\sqrt{ab*a^4b^2}=\sqrt{a^5b^3} \\ \\ 0,2\sqrt5=\dfrac{1}{5}\sqrt{5}=\sqrt{\Big(\frac{1}{5}\Big)^2*5}=\sqrt{\frac{5}{5^2}}=\sqrt{\frac{1}{5}}=\sqrt{0,2}$