Question

Va rooog, ajutati-ma!!!

Answer 1

tg x=2 <=> sin x/cos x =2 => sin x = 2cos x
sin x + cos x = 2 cos x + cos x = 3 cos x
sin x - cos x = 2 cos x - cos x = cos x
sin x + cos x / sin x - cos x = 3 cos x / cos x = 3

Answer 2

$tgx=2 =\ \textgreater \ \frac{sinx}{cosx} =2=\ \textgreater \ sinx=2cosx$

$\frac{sinx+cosx}{sinx-cosx} = \frac{2cosx+cosx}{2cosx-cosx} = \frac{3cos}{cosx} = 3$