VA ROOOG ajutati-ma cu tema la chimie! DAU CORANA
1. Calculati numarul de moli de hidrogen care se afla in 4 moli de acid sulfuric.
2. Ce cantitate de oxigen exprimata in grame se gaseste in 2 moli de CaO.
3. Ce cantitate de oxigen exprimata in grame se gaseste in 36g apa.
4. Determinati masa de apa care cantareste 36 g oxigen.
5. Determinati masa de amoniac in care se gasesc 28 g azot.
6. Determinati nr. de moli de oxigen
Ah=1
Ao=16
An=14
AMg=2
ACa=40
As=32
Răspunsuri la întrebare
Răspuns de
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4 moli H2S04 1 mol H2SO4--------1molH2
Xmoli H2 4moliH2SO4-------X moli H2
X=4 moli H2
2moli CaO MCaO=40+16=56
X g O2 56 g CaO-------------1 mol CaO
X gCaO----------------2 moli CaO
X=56.2=112 g CaO
56 g CaO---------16 gO
112 gCaO----------Y gO
Y=112.16:56=32 g O2
36gH2O MH2O=2+16=18
Xg O2 18g H2O---------16 gO
36 gH2O---------XgO
X=36.16:18=32 g O
36 g O2 MH2O=18
XgH2O 18 g H2O---------16 g O
XgH2O----------36 gO
X=18.36:16=40,5 g H2O
28g NH3 MNH3=14+3=17
XgN2 17g NH3-------------14 gN2
28 g NH3------------X gN2
X=28.14:17=23,05 gN2
Punctul 6 nu este complet
Xmoli H2 4moliH2SO4-------X moli H2
X=4 moli H2
2moli CaO MCaO=40+16=56
X g O2 56 g CaO-------------1 mol CaO
X gCaO----------------2 moli CaO
X=56.2=112 g CaO
56 g CaO---------16 gO
112 gCaO----------Y gO
Y=112.16:56=32 g O2
36gH2O MH2O=2+16=18
Xg O2 18g H2O---------16 gO
36 gH2O---------XgO
X=36.16:18=32 g O
36 g O2 MH2O=18
XgH2O 18 g H2O---------16 g O
XgH2O----------36 gO
X=18.36:16=40,5 g H2O
28g NH3 MNH3=14+3=17
XgN2 17g NH3-------------14 gN2
28 g NH3------------X gN2
X=28.14:17=23,05 gN2
Punctul 6 nu este complet
ioanaisabela58:
MULTUMESC MULT!
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