Question

Va rooog. dau coronitaaaaaaaaa dar si cu explicatiiiiiiiii​

Answer 1

Răspuns:

se inmultesc termenii pe diagonala

la impartirea a doua fractii a doua fractie se intoarce si se face operatia de inmultire

x·0,(12)=(³⁾1/2-1/6)·(3/2+6/5·5/4)

0,(12)=12/99=4/33

4x/33=(3/6-1/6)·(3/2+3/2)

4x/33=2/6·6/4 la inmultire se simplifica termenii pe diagonala

4x/33=1/2

2·4x=33

8x=33=>x=33/8=4,125

____________

[·(1·9+7)/9·3/8]·(²⁾11/15-1/30)=x·14/5

(16/9·3/8)·(22/30-1/30)=14x/5

2/3·21/30=14x/5

42/60=14x/5

14x·60=42·5

840x=210

x=210/840

x=0,25