Matematică, întrebare adresată de tamasanuandrei, 9 ani în urmă

Va rooog ex 12,13,14 pana la 11:30

Anexe:

icecon2005: prea scurt timpul!Succes!!!

Răspunsuri la întrebare

Răspuns de icecon2005
0
a) 3x+1\frac{1}{3} =2x+5 \frac{2}{6} \\ \\ 3x+\frac{3+1}{3} =2x+\frac{30+2}{6} \\ \\ \frac{9x+4}{3} = \frac{12x+32}{6} \\ \\ \frac{9x+4}{3} - \frac{12x+32}{6}=0 \\ \\ \frac{18x+8}{6} - \frac{12x+32}{6} =0 \\ \\ \frac{18x-12x+8-32}{6} =0 \\ \\ 18x-12x+8-32=0 \\ \\ 6x=32-8 \\ \\ 6x=24 \\ \\ x=4 \\ \\

c)3 \frac{2}{5} *x-1 \frac{1}{2}=x-2 \frac{7}{10}   \\  \\  \frac{17x}{5} - \frac{3}{2} =x- \frac{27}{10}  \\  \\ \frac{17x}{5}-x= \frac{3}{2}- \frac{27}{10} \\  \\  34x-10x=15-27 \\  \\ 24x=-12 \\  \\ x=- \frac{1}{2}

e) (x-1 \frac{3}{4}):(1 \frac{5}{4} -2 \frac{3}{4})=1 \frac{1}{3}  \\  \\ (x- \frac{7}{4}):( \frac{9}{4}- \frac{11}{4})= \frac{4}{3} \\  \\  \frac{4x-7}{4}:(\frac{-2}{4})= \frac{4}{3}  \\  \\  \frac{4x-7}{4}*( \frac{-4}{2})= \frac{4}{3} \\  \\  \frac{7-4x}{2}- \frac{4}{3}=0 \\  \\ 3(7-4x)-4*2=0 \\  \\ 21-12x-8=0 \\  \\ 13=12x \\  \\ x= \frac{13}{12}=1 \frac{1}{12}
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