Question

va rooog urgenttttttt

Answer 1

a.) 6BD+DC=168
      BD+DC=60

rezolvam in sistem de ecuatii
BD-x; DC - y

6x+y=168
x+y=60

eu voi rezolva prin metoda reducerii
x a 2-a cu -1

6x+y=168
-x-y=-60

x+y=60
5x=108

x+y=60
BD=x=108/5=21intreg3/5
Dc=y=60-21 3/5=38 2/5

AD²=BD·DC
Ad=√BD·DC=√108/5 · 192/5=√20736/25

b) notam cu x - o parte, atunci BD=9x, CD=16x
CD-Bd=16x-9x=7x
7x=14
x=14/7=2
Bd=9·2=18
CD=16·2=32
AD=√18·32=√2·9·2·16=24
Bc=18+32=50
Ab=√BD·Bc=√18·50=√2·9·5·5·2=30
Ac=√Dc·BC=√32·50=√16·2·5·5·2=40