Question

Va roooog!
Calculati suma dintre a si triplul lui b stiind ca:
a=(32+8):4:2+[(25*17-19-6):2-100+20]:4

230-{4*[2+5*(98-5*b)-137]}=10

Answer 1

a = 40:4:2+[(425 - 19-6):2-100+20]:4
a = 10:2+[(406-6):2-100+20]:4
a = 5+(400:2-100+20):4
a = 5+(200-100+20):4
a = 5+(100+20):4
a = 5+120:4
a = 5+30
a = 35

230-10 = 4*[2+5*(98-5*b)-137]
220 = 4*[2+5*(98-5*b)-137]
220:4 = 2+5*(98-5*b)-137
55 = 2+5*(98-5*b)-137
55-2 = 5*(98-5*b)-137
53 = 5*(98-5*b)-137
53+137 = 5*(98-5*b)
190 = 5*(98-5*b)
190:5 = 98-5*b
38 = 98-5*b
5*b = 98-38
5*b = 60
b = 60:5
b = 12

a+3b = 35+ 3*12 = 35+36 = 71