Question

va roooog frumos dau coroanaaa

Answer 1

2a²(b-1)+ 2b²(a+1)=(a+b)( a²+b²+1)

2a²b- 2a²+2ab²+2b²=a³+ ab²+a+a²b+b³+b

2a²b-a²b+2ab²-ab²-2(a²-b²)=a+b+( a³+ b³)

a²b+ ab²-2(a-b)(a+b)=a+b+(a+b)( a²-ab+b²)

ab(a+b)-2(a-b)(a+b)= (a+b)(1+ a²-ab+b²)

(a+b)[ab-2(a-b)]= (a+b)(1+ a²-ab+b²)   /:(a+b)

ab-2(a-b)=1+ a²-ab+b²

-2(a-b)=1+ a²-2ab+b²

-2(a-b)=1+ (a-b)²

(a-b)²+ 2(a-b)+1=0 ;    e patrat perfect

(a-b+1) ²=0

=> a-b+1=0=> b=a+1

deci, a si b sunt consecutive