Question

Va rooooggg, îmi trebuieeee!

Answer 1

7.
a)rad3(2-rad3)/3 = (2rad3-3)/3
b)rad5(1-rad5)/15 = (rad5-5)/15
c)rad11(rad22-rad33)/22 = (11rad2-11rad3)/22 = 11(rad2-rad3)/22 = (rad2-rad3)/2
d)rad3(4rad5-3rad5)/15 = rad15/15

Answer 2

$a) \frac{2 - \sqrt{3} }{ \sqrt{3} } = \frac{(2 - \sqrt{3}) \sqrt{3} }{ \sqrt{3} \sqrt{3} } = \frac{2 \sqrt{3} - 3 }{3}$
$b) \frac{1 - \sqrt{5} }{3 \sqrt{5} } = \frac{(1 - \sqrt{5}) \sqrt{5} }{3 \sqrt{5} \sqrt{5} } = \frac{ \sqrt{5} - 5 }{3 \times 5} = \frac{ \sqrt{5} - 5 }{15}$
$c) \frac{ \sqrt{22} - \sqrt{11} }{2 \sqrt{11} } = \frac{( \sqrt{22} - \sqrt{11}) \sqrt{11} }{2 \sqrt{11} \sqrt{11} } = \frac{ \sqrt{242} - 11 }{2 \times 11} = \frac{11 \sqrt{2} - 11 }{22} = \frac{11( \sqrt{2} - 1) }{22} = \frac{ \sqrt{2} - 1 }{2}$
$d) \frac{ \sqrt{80} - \sqrt{45} }{ \sqrt{75} } = \frac{4 \sqrt{5} - 3 \sqrt{5} }{ \sqrt{75} } = \frac{ \sqrt{5} }{75} = \frac{ \sqrt{5} }{ \sqrt{5} \sqrt{15} } = \frac{1}{ \sqrt{15} } = \frac{1 \sqrt{15} }{ \sqrt{15} \sqrt{15} } = \frac{ \sqrt{15} }{15}$