Question

Va roooooggg!!! Am nevoie urgennntttt!!!

Answer 1

   
[tex]\displaystyle\\ e)\\ \frac{2^{2000}}{2^{1998}+2^{1995}}\times\frac{5^2-4^2}{2^7-2^3}=\\\\ =\frac{2^{2000}}{2^{1995+3}+2^{1995}} \times \frac{5^2-4^2}{2^7-2^3}=\\\\ =\frac{2^{2000}}{2^{1995}\times2^3+2^{1995}}\times\frac{25-16}{128-8}=\\\\ =\frac{2^{2000}}{2^{1995}(2^3+1)}\times\frac{25-16}{128-8}=\\\\ =\frac{2^{2000-1995}}{2^3+1}\times\frac{25-16}{128-8}=\\\\ =\frac{2^{5}}{8+1}\times\frac{25-16}{128-8}=\\\\ =\frac{32}{9}\times\frac{9}{120}=\frac{32}{120}=\boxed{\bf\frac{4}{15}}[/tex]