Question

va roooooog muuuult!!!!!!!!!!!

Answer 1

xyzt divizibil cu 10 => t=0
y divide 10=> y∈{1,2,5}
11 divide y+6 => singura valoare a lui y din multimea de mai sus care satisface aceasta conditie este 5 => y=5
$\frac{1}{z-3}= \frac{3 \frac{1}{2} }{4- \frac{1}{2} }= \frac{ \frac{7}{2} }{ \frac{7}{2} }= 1=\ \textgreater \ z-3=1=\ \textgreater \ z=4$
x+z=y=>x=y-z=5-4=1=>xyzt=1540