Question

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Answer 1

Răspuns:

a)

$( ^{2)} \frac{11}{6} + ^{3)}\frac{3}{4} ) \div \frac{31}{24} =$

$( \frac{22}{12} + \frac{9}{12} ) \div \frac{31}{24} =$

$\frac{31}{12} \times \frac{24}{31} =$

$2$

b)

$( ^{3)} \frac{5}{6} + ^{2)}\frac{11}{9} ) \div \frac{74}{9} =$

$( \frac{15}{18} + \frac{22}{18} ) \times \frac{9}{74} =$

$\frac{37}{18} \times \frac{9}{74} =$

$\frac{1}{2} \times \frac{1}{2} =$

$\frac{1}{4}$

c)

$( ^{4)} \frac{1}{6} + ^{3)}\frac{17}{8} ) \div \frac{77}{24} + \frac{2}{7} =$

$( \frac{4}{24} + \frac{51}{24} ) \times \frac{24}{77} + \frac{2}{7} =$

$\frac{55}{24} \times \frac{24}{77} + \frac{2}{7} =$

$5 \times \frac{1}{7} + \frac{2}{7} =$

$\frac{5}{7} + \frac{2}{7} =$

$\frac{7}{7} =$

$1$

Answer 2

$\it a)\ \ \Big(\dfrac{^{2)}11}{\ 6}+\dfrac{^{3)}3}{\ 4}\Big):\dfrac{31}{24}=\dfrac{22+9}{12}\cdot\dfrac{24}{31}=\dfrac{\not31}{12}\cdot\dfrac{24}{\not31}=\dfrac{24}{12}=2\\ \\ \\ b)\ \ \Big(\dfrac{^{3)}5}{\ 6}+\dfrac{^{2)}11}{\ 9}\Big):\dfrac{74}{9}=\dfrac{15+22}{18}\cdot \dfrac{9}{74}=\dfrac{\not37}{\not18\ ^2}\cdot\dfrac{\not9}{\not74\ ^2}=\dfrac{1}{4}$

$\it c)\ \ \Big(\dfrac{^{4)}1}{6}+\dfrac{^{3)}17}{8}\Big):\dfrac{77}{24}+\dfrac{2}{7}=\dfrac{4+51}{\not24}\cdot\dfrac{\not24}{77}+\dfrac{2}{7}=\dfrac{\ 55^{(11} }{77}+\dfrac{2}{7}=\dfrac{5}{7}+\dfrac{2}{7}=\dfrac{7}{7}=1$