Question

va rooooooog mult ,dau si coroana​

Answer 1

$\it \bigg(\dfrac{2}{3}a^{-4}b^{-2}\bigg)^{-2}=\bigg(\dfrac{2}{3}\bigg)^{-2}\cdot(a^{-4})^{-2}\cdot(b^{-2})^{-2}=\dfrac{9}{4}a^8b^4$