Question

Va roooooooooooog!!!!

Answer 1

2)
3) a = 4,12 si b = 37/9
    b = 4,(1)
    b < a
    4,(1) < 4,12
4) 53/7 si        3 si 1/5
    3 si 1/5 = 16/5
    53/7 = 7,5714
    16/5 = 3,2
    53/7 > 16/5 cu 4,3714
    7,5714 - 3,2 = 4,3714
5) a * b = 9/5   si  c = 20/27
    a * (b * c) = (a * b) * c = 9/5 * 20/27 = 4/3

Answer 2

2) 1,49 ≈ 1,4 (prin lipsă la o zecime).

3)

$\it b = \dfrac{37}{9} = 4\dfrac{1}{9} =4,(1)\ \textless \ 4,12=a$

4)

 [tex]\it \dfrac{53}{7} - 3\dfrac{1}{5} = 7\dfrac{4}{7} -3\dfrac{1}{5} = (7-3) +(\dfrac{^{5)}4}{\ 7}-\dfrac{^{7)}1}{\ 5}) = 4+\dfrac{20-7}{35}= \\\;\\ \\\;\\ = 4\dfrac{13}{35}[/tex]

Prin urmare:

$\it \dfrac{53}{7 } \ \textgreater \ 3\dfrac{1}{5} \ cu \ 4\dfrac{13}{35}$


5) a·(b·c) = (a·b)·c = (9/5)·(20/27) = 4/3 = 1,(3)