Question

Va rrog foarte urgent!

Answer 1

(n+2) / (3n-4)>0
n+2 > 3n-4
2n< 6
n<3
n={0,1,2}

Answer 2

$\displaystyle \frac{n+2}{3n-4} \ \textgreater \ 0 \\ n+2\ \textgreater \ 3n-4 \\ n-3n\ \textgreater \ -4-2 \\ -2n\ \textgreater \ -6 \\ 2n\ \textless \ 6 \\ n\ \textless \ \frac{6}{2} \\ n\ \textless \ 3 \\ x \in \{0;1;2\}$