Question

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Answer 1

$i^{2k + 1} = - 1.\\i^{2003} + \frac{1}{i^{2003}} = -1 + (-1) = -2.\\Raspuns: i^{2003} + \frac{1}{i^{2003}} = -2.$

k ∈ N, 2k + 1 reprezinta orice numar impar.