vaaaaa rpgggggggg!!!!
Răspunsuri la întrebare
a)AO=3 dm+3 dm=6 dm = 0,6 m
Ac=Pi*AO^2=3,14*0,6*0,6=3,14*0.36=1,1304 m^2
Lc=2*Pi*AO=2*3,14*0.6=6,28*0,6=3,768 metri
b)S=Pi*OM*OM=3,14*0,3*0,3=3,14*0,09=0,2826 m^2
C=2*Pi*OM=2*3,14*0,3=6,28*0,3=1,884 m
c)nu stiu la ce suprafata se refera
d) Avem 4 triunghiuri dreptungice isoscele cu unghiuri de 45 de grade, deci unghiurile MNP NPQ PQM QMN au cate 90 de grade si avem teorema lui pitagora de 4 ori MN=NP=PQ=QM=radical din (OM^2+ON^2)=radical(2*0,3^2)=0,3*radical(2)=0,3*1,41=0,423 m
Aria egal cu MN*NP=0,3*radical(2)*0,3*radical(2)=0.09*2=0,18 m^2
Perimetrul=4*MN=4*0,423=1,692 m
e) La fel avem triunghiuri dreptungice isoscele AOB, BOC, COD si DOA Deci avem un patrat ABCD cu unghiurile de 90 de grade si laturile egale.
AB=BC=CD=DA=radical(0,6*0,6+0,6*0,6)=radical(0,6^2(1+1))=0,6*radical(2)=0,6*1,41=0,846 m
Aria=0,6*radical(2)*0,6*radical(2)=2*0,6*0,6=2*0,36=0,72 m^2
Perimetrul= 4*0,6*radical(2)=0,24*1,41=0,3384 m
a)AO=3 dm+3 dm=6 dm = 0,6 m
Ac=Pi*AO^2=3,14*0,6*0,6=3,14*0.36=1,1304 m^2
Lc=2*Pi*AO=2*3,14*0.6=6,28*0,6=3,768 metri
b)S=Pi*OM*OM=3,14*0,3*0,3=3,14*0,09=0,2826 m^2
C=2*Pi*OM=2*3,14*0,3=6,28*0,3=1,884 m
c)nu stiu la ce suprafata se refera
d) Avem 4 triunghiuri dreptungice isoscele cu unghiuri de 45 de grade, deci unghiurile MNP NPQ PQM QMN au cate 90 de grade si avem teorema lui pitagora de 4 ori MN=NP=PQ=QM=radical din (OM^2+ON^2)=radical(2*0,3^2)=0,3*radical(2)=0,3*1,41=0,423 m
Aria egal cu MN*NP=0,3*radical(2)*0,3*radical(2)=0.09*2=0,18 m^2
Perimetrul=4*MN=4*0,423=1,692 m
e) La fel avem triunghiuri dreptungice isoscele AOB, BOC, COD si DOA Deci avem un patrat ABCD cu unghiurile de 90 de grade si laturile egale.
AB=BC=CD=DA=radical(0,6*0,6+0,6*0,6)=radical(0,6^2(1+1))=0,6*radical(2)=0,6*1,41=0,846 m
Aria=0,6*radical(2)*0,6*radical(2)=2*0,6*0,6=2*0,36=0,72 m^2
Perimetrul= 4*0,6*radical(2)=0,24*1,41=0,3384 m