Question

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Answer 1

Salut!

m∈R,m=?

$x^{2} -(m^{2} +3)x+2m+1=0\\a=1, b=-(m^{2}+3),c=2m+1\\x1+x2+x1x2=7\\S=x1+x2=\frac{-b}{a} =m^{2}+3\\P=x1x2=\frac{c}{a} =2m+1\\m^{2}+3+2m+1=7=>m^{2}+2m-3=0\\a=1,b=2,c=-3.DELTA=4+12=16\\m1=\frac{-b+\sqrt{DELTA} }{2a} =\frac{-2+4}{2} =1\\m2=\frac{-2-4}{2} =-3\\S=-3,1$

Bafta!