Question

VABCD piramida patrulatera regulata
m=6 cm
l=4 cm
ap,h=?
Ofer coroana!!!

Answer 1

$m^{2} = h^{2} + \frac{ l^{2} }{2}$
deci:
$h^{2} = m^{2} - \frac{ l^{2} }{2}$
$h^{2} = 6^{2} - \frac{ 4^{2} }{2}$
$h^{2} = 36 - \frac{ 16 }{2}$
$h = \sqrt{24}=2 \sqrt{6}$ cm
apotema bazei este ab=2 şi apotema piramidei va fi
$ap^{2} = h^{2} + ab^{2}$
$ap^{2} = (2 \sqrt{6})^{2} + 2^{2}$
$ap^{2} = 28$
$ap = 2 \sqrt{7}$