Question

Valorile  naturale ale lui n pentru care 18/2n+1 ∈ N sunt.......
REPEDEE!!!

Answer 1

swe cauta divizorii lui 18={-1,-2,-3,-6,-9,-18 ,18,9,6,,3,2,1]
2n+1=1 ,n=0
2n+1=2 ,∉N
2n+1=3,n=1
2n+1=6∉N
2n+1=9,n=4
2n+1=18∉N
n={0,1,4}