Question

varog exercitiul 18 varog

Answer 1

a)  8+3/7-(2+2/5)=(8x7+3)/7 - (5x2+2)/5=59/7-12/5=[(59x5)-(12x7)]/[5x7]

=> (295-84)/35=211/35=6+1/35

b)  3+11/15 - (1+7/10)=(3x15+11)/15 - (10+7)/10 = 56/15 - 17/10

=> (56x2 - 17x3)/30=(112-51)/30=61/30=2+1/30

c)  1-5/12=12/12 - 5/12=7/12

d) 8-6/11=(8x11-6)/11=(88-6)/11=82/11

e) 6-(1+2/9)=6-([9+2]/9)=6-11/9=(6x9-11)/9=(54-11)/9=43/9

f)  2+1/18 - 1/9 = (2x18+1-1x2)/18=(36+1-2)/18=35/18=1+17/18

g) 6+3/8-(2+3/4)=(6x8+3)/8 - (2x4+3)/4 = 51/8 - 11/4 = (51-11x2)/8

=>(51-22)/8=29/8=3+5/8

h) 4+2/15 - (3+5/12)=(4x15+2)/15 - (3x12+5)/12=(60+2)/15 - (36+5)/12

=> 62/15-41/12=(62x12 - 41x15)/(15x12)=(744-615)/180=129/180 

simplificam prin 3 si   => 43/60