Question

vărog mult ajutaţimă​

Answer 1

Răspuns,explicație pas cu pas:

1.

$=x^{2} +2x*3+3^{2} =\\=x^{2} +6x+9$

2.

$=(2y)x^{3} -3*(2y)^{2} *1+3*2y*1^{2} -1^{3} =\\=8y^{3} -3*4y^{2} *1+3*2y*1-1=\\=8y^{3}-12y^{2} +6y-1$

3.

$=(3a)^{2} -2^{2} =\\=9a^{2}-4$

4.

$=y*3y-4y+7*3y-7*4\\=3y^{2} -4y+21y-28=\\=3y^{2} +17y-28$

5.

$=5x-10-(16+8x+x^{2} )=\\=5x-10-16-8x-x^{2} =\\=-3x-26-x^{2} =\\=-x^{2} -3x-26$

6.

$=x^{3} -3^{3} =\\=(x-3)*(x^{2} +x*3+3^{2} )=\\=(x-3)*(x^{2} +3x+9)$

Succes! (am scris direct raspunsul)