Question

varog mult problema din imagine,dau coroana​

Answer 1

Răspuns:

Explicație pas cu pas:

c₁=cateta 1

c₂= cateta 2

ip= ipotenuza

pr - proiectia

h= inaltimea

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c₁/c₂=5/12

c₁=5*c₂/12

ip=26 cm

c₁²+c₂²=ip²

(5*c₂/12)²+c₂²=26²

25c₂/144+¹⁴⁴⁾c₂²=¹⁴⁴⁾26²

25c²₂+144c²₂=144*26²

25c₂²+144c₂²=12²*26²

169c₂²=(12*26)²

c₂=12*26/13=12*2=24 cm (cateta a doua)

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c₁=(5*24)/12=120/12= 10 cm ( prima cateta)

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aplicam teorema catetei

c₁²=pr₁*ip

10²=pr₁*26

100=pr₁*26

pr₁=100/26

pr₁=3,84 cm ( proiectia primei catete)

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c₂²=pr₂*ip

24²=pr₂/26

576=pr₂/26

pr₂=22,16 cm (proiectia celei de a doua catete)

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h=(c₁*c₂)/ip= (24*10)/26=240/26=9,23 cm