Question

verifica egalitate:
•12x3x10-(100+35:5)=50x2+25x4+(309-200-3x8);
•136-(9x9+5x6)=450-(320+6x7-3x5).

​

Answer 1

Răspuns:

36×10-(100+7)=360-107=253

100+100+(109-24)= 200+85=285

Prima egalitate nu e corecta

136-(81+30)=136-111=25

450-(320+42-15)=450-(362-15)=450-347=103

nici a doua nu e corecta