Question

verifică egalitatile: a)(45+25)÷10+53=(9×13)-8×(3+4)

; b) 100-(43-27)×(72÷9-3)=56÷7÷(4+4)×20​

Answer 1

a) (45+25)÷10+53=(9×13)-8×(3+4)

70÷10+53= 117-8×7

7+53=117-56

60=61         Fals

b) 100-(43-27)×(72÷9-3)=56÷7÷(4+4)×20​

100-16×(8-3)= 8÷8×20

100-16×5=1×20

100-80=20

20=20      Adevarat