Question

Verificați inegalitatea mediilor pentru a=3 b=12

Answer 1

$\textbf{Inegalitatea mediilor:}\\\\ \dfrac{a+b}{2}\geq \sqrt{ab}\\\\ \\ a = 3,\quad b = 12: \\\\ \Rightarrow \dfrac{3+12}{2} \geq \sqrt{3\cdot 12}\\\\ \Rightarrow \dfrac{15}{2}\geq \sqrt{36}\\\\\Rightarrow 7,5 \geq 6\quad (A)$