Question

Verificati relatia mh<mg<ma pentru perechile de numere 5 si 7,2 ​

Answer 1

Media aritmetică (5, 7,2) = (5 + 7,2)/2 = 12,2/2 = 6,1

Media geometrică (5, 7,2) = radical (5 × 7,2) = radical (5 × 72/10) = radical (72/2) = radical 36 = 6

Media armonică (5, 7,2) = 2 × 5 × 7,2/(5 + 7,2) = 72/12,2 = 720/122 = 360/61 < 6

Atunci mh(5, 7,2) < mg(5, 7,2) < ma(5, 7,2)