Question

vo rog mult imi trebuie repede​

Answer 1

Răspuns:

Explicație:

1.

12,044.10 la 25 = 1204,4 .10²³

1mol NH3---------6,022.10²³ molecule NH3

xmoli NH3--------------1204,4.10²³molecule NH3

x=n= 1204,4 .10²³ : 6,022.10²³= 200 moli NH3

m= n . M

MNH3= 14 + 3=17--------> 17g/moli

m= 200moli .17g/moli= 3400 g NH3

2.

MSO3= 32 + 3.16= 80-------> 80g/moli

n= 160g : 80g/moli= 2moli SO3

1mol SO3------------ 3 .  6,022.10²³atomi O

2moli SO3----------------x

x= 2 . 3 . 6,022.10²³ = 36,132.10²³atomi O