Question

vreau rezolvare. Dau coroana :)
rezultatul trebuie sa fie 4 radical 2 supra 3

Answer 1

Am găsit ca x=5
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Answer 2

   
[tex]\displaystyle\\ \frac{1}{ \sqrt{8} - \sqrt{x} } + \frac{1}{ \sqrt{8} + \sqrt{x} } =\\\\\\ = \frac{ \sqrt{8} + \sqrt{x} +\sqrt{8} - \sqrt{x} }{ (\sqrt{8} - \sqrt{x})(\sqrt{8} -\sqrt{x})}= \\\\\\ = \frac{ \sqrt{8} +\sqrt{8} }{ 8 - x}= \frac{ 2\sqrt{8}}{ 8 - x}=\frac{ 4\sqrt{2}}{ 8 - x}\\\\\\ \frac{ 4\sqrt{2}}{ 8 - x}=\frac{ 4\sqrt{2}}{ 3}\\\\\\ \Longrightarrow~~8-x = 3 \Longrightarrow~~x = 8-3 = \boxed{\bf 5} [/tex]