Question

Vreau rezolvarea .....................

Answer 1

MFe=56g/mol
MAl=27g/mol
mAl=101.25g

n=m/M=101.25/27=3.75 moli Al

2mol..1mol...........1mol.....2mol
2Al + Fe2O3 –– Al2O3 + 2Fe + Q
3.75mol..x=1.875...y=1.875...z=3.75 moli Fe

n=m/M==>m=n*M=3.75*56=210g Fe impur

0.8*210=168g Fe pur

54g.....160g........102g......112g
2Al + Fe2O3 –– Al2O3 + 2Fe + Q
101.25g..x=300g....y=191.25g...z=210g Fe impur

p=mpur/mipur*100==>mpur=p*mipur/100=80*210/100=168g Fe pur