Question

Vreau si eu la 5 plz repede da vreau si cu rezolvare dau coroana repede plz

Answer 1

   
[tex]E(x)=2(4x+1)(1-4x) + (4x-3)^2 + (3+4x)^2 = \\ \\ =2(1+4x)(1-4x) + (4x-3)^2 + (4x+3)^2 = \\ \\ =2[1^2 -(4x)^2] + [(4x)^2 - 2 \cdot 4x \cdot 3 + 3^2] + [(4x)^2 + 2 \cdot 4x \cdot 3 + 3^2] = \\ \\ =2[1 -16x^2] + [16x^2 - 24x + 9] + [16x^2 + 24x + 9] = \\ \\ =2 -32x^2 + 16x^2 - 24x + 9 + 16x^2 + 24x + 9 = \\ \\ =\underbrace{- 32x^2 + 16x^2 + 16x^2}_{=0} \underbrace{- 24x + 24x }_{=0}+ \underbrace{2+ 9 + 9}_{=20} = 0 + 0 + 20= \boxed{20} \\ \\ \texttt{cctd}[/tex]