Question

Vreau si eu rezolvarea la acest exercitiu va rog ​

Answer 1

Răspuns:

$a) (x^{2} +3x-3x-9)(x^{2} +9)- x^{4} -4x^{2} -4 +3x^{2} -6x+3=$

= $(x^{2}-9)(x^{2} +9) -x^{4} -x^{2} -6x-1$  =

$x^{4} +9x^{2} -9x^{2} -81$ $- x^{4} -x^{2} -6x-1$=  -$x^{2}$-6x -82

b) $x^{3} -x +5x^{2} -5 -x^{3} -8x^{2} -16x +x^{2} +2x+1=$ -2$x^{2}$-15x -4

c) $9x^{2} y^{2} -15xy+15xy -25 - (9x^{2} y^{2} -12xy+4)=$ 9$x^{2} y^{2}$ -25- 9$x^{2} y^{2}$+12xy- 4=

12xy-29

d) (5x-8) (2x+2+ 3x+6) - (3x-4) ( 5x+10- 2x-6)= (5x-8) (5x+8) - (3x-4)(3x+4)=

25$x^{2}$- 40x+40x- 64 - (9$x^{2}$ +12x-12x-16)= 25$x^{2}$ -64 - 9$x^{2}$ +16= 16$x^{2}$-48 = 16($x^{2}$-3)