Question

Vreau si eu sa stiu cum se rezolva ecuatia:
A*A+A=-6

Answer 1

a^2 + a +6 = 0
a1,2 = (-1+/- rad(1-24)) : 2 = -1/2 +/- (i/2  *  rad23)  ∈ C-R.
i=rad(-1).

Answer 2

$A \times A + A = - 6$

${A}^{2} + A = - 6$

${A}^{2} + A + 6 = 0$

$a = 1$

$b = 1$

$c = 6$

$\Delta = {b}^{2} - 4ac$

$\Delta = {1}^{2} - 4 \times 1 \times 6$

$\Delta = 1 - 24$

$\Delta = - 23 < 0 = > ecuatia \: nu \: are \: radacini \: reale$

$= > ecuatia \: are \: radacini \: complexe$

$A_{1,2} = \frac{ - b\pm \: i \sqrt{ \Delta} }{2a} = \frac{ - 1\pm \: i \sqrt{ - 23} }{2 \times 1} = \frac{ - 1\pm i\:\sqrt{ ( - 23) }}{2}$

$A_{1} = \frac{ - 1 +\:i \sqrt{-23} }{2}$

$A_{2} = \frac{ - 1 -\:i \sqrt{-23} }{2}$