Question

Vreau si eu va rog frumos exercitiul 12. Daca sunteti in clasa a V-a este in culegerea de matematica la pagina 99. Ajutooooor.

Answer 1

a)16(5(8*5^x+9)-10^3)/9=80=>16(5(8*5^x+9)-10^3)=9*80=>
5(8*5^x+9)-10^3=720/16=>5(8*5^x+9)-10^3=45=>5(8*5^x+9)=45+10^3=>
8*5^x+9=1045/5=>8*5^x+9=209=>8*5^x=200=>5^x=25=>x=5.
c)2^x=8^8=>2^x=(2^3)^8=>2^x=2^24=>x=24
e)2x^3=16=>x^3=8=>x=2
b)x^3=27²=>x^3=(3^3)^2=3^6=(3^2)^3=>x=9
d)2004^3*x=0=>x=0.
f)32*2^x=4^12=>2^5*2^x=(2^2)^12=>2^(5+x)=2^24=>5+x=24=>x=19
g)2(x+15)+12=2^3(2^2*7*2*1)
2x+30+12=2^6*7=>x=(2^6*7-42)/2=32*7-21=7(32-3)=7*29=203.